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The inverse Laplace transform
The inverse Laplace transform is described by
Eq. (A.2). As already mentioned in
section 2.2 in many cases a direct
evaluation of the complex
inverse integral
is not necessary, as the most important elementary functions are
given in Table 2.1. A complicated function,
,
not given in Table 2.1 must be decomposed into a sum
of simple functions of
that is
 |
(2.15) |
which have a known inverse Laplace transform:
 |
(2.16) |
For many problems in control the function
is a ratio of
polynomials in s, known as rational
fraction, that is
 |
(2.17) |
where
and
are the numerator and the denominator,
respectively.
If
, then
is divided by
, where a polynomial in
and a ratio of polynomials are
obtained. The numerator of the fraction
has a lower
order than
. E.g, if
, then
 |
(2.18) |
whereby
and
and
are
constants.
A rational fraction
given in
Eq. (2.17) can be decomposed into more simple functions
by application of partial fraction decomposition,
as shown in Eq. (2.15).
In order to perform this decomposition the denominator polynomial
must be factorised into the form
 |
(2.19) |
For a denominator polynomial of
-th order one obtains
roots
or zeros
. The zeros of
are also known as the poles of
, since
they define where
is infinite. The partial fraction
decomposition for different types of poles is shown in the
following.
Case 1:
has only single
poles.
Here
can be expanded into the form
 |
(2.20) |
where the residuals
are real or
complex constants. Using the table of correspondences one
immediately can obtain the corresponding function of time
for  |
(2.21) |
The values
can be determined either by comparing the
coefficients or by using the
theorem of
residuals from the theory of functions according to
 |
(2.22) |
for
with
.
Case 2:
has multiple
poles.
For multiple poles of
each with multiplicity
the corresponding partial fraction decomposition is
with |
(2.23) |
The back transformation of Eq. (2.23) into the time
domain is
for  |
(2.24) |
The real or complex coefficients
for
determined by the theorem of residuals are
 |
(2.25) |
This general relation also contains the case of single poles of
. The poles may be real or complex.
Case 3:
has also conjugate complex
poles.
As both, the numerator
and the denominator
of the
function
are rational algebraic functions, complex factors
always arise as conjugate complex pairs. If
has a
conjugate complex pair of poles
, then for the function
in the
partial fraction decomposition of
Eq. (2.20) can be applied to give
 |
(2.26) |
where the residuals
are also a conjugate complex pair. Therefore, both fractions of
can be combined, and one obtains
 |
(2.27) |
with the real coefficients
 |
(2.28) |
The determination of the coefficients
and
is performed again using the theorem
of residuals by
 |
(2.29) |
As
is complex, both sides of this equation are complex.
Comparing the real and imaginary parts of both sides one gets two
equations for the calculation of
and
. This
procedure is demonstrated now using the following example.
Example 2.4.1
Find the inverse Laplace transform

of
The partial fraction decomposition of

is
where the function

contains the conjugate pair of
poles
In addition the third pole of

is
For the coefficients

and

it follows from
Eq. (
2.29)
Comparing the real and imaginary parts on both sides one obtains
and  |
|
and from this finally

.
Using Eq. (2.22) the residual is
The partial fraction decomposition of

is thus
which can be rearranged in the form
such that correspondences given in Table
2.1 can be
directly applied to find the inverse transformation. Using the
correspondences 16, 15 and 6 of this table, it follows that
for  |
|
which can be rearranged as
for  |
|
The graphical representation of

is shown in
Figure
2.1a. Figure
2.1b shows the
corresponding poles, marked by a x, for this

in the complex

plane.
Figure 2.1:
(a) Graph of the original function
(function in the time domain)
and (b) position of the poles of
in the
plane
 |
It can be seen from this example that the position of the poles
and
affects the shape of the graph of
. In this case all poles of
have negative real parts,
therefore the graph of
shows a damped behaviour, i.e. it
decreases to zero for
. If the
real part of one pole be positive, then the graph of
would be infinitely large for
.
Since in control problems the original
function
always represents the time behaviour of a system
variable, the behaviour of this system variable
can be
judged to a large extent by investigation of the positions of the
poles of the corresponding mapped function
. This will be
further commented on in later sections.
Next: Solving linear differential equations
Up: The Laplace transform
Previous: Main theorems of the
  Contents
Christian Schmid 2005-05-09